Fundimental Units

BlueEagle's picture
Submitted by BlueEagle on Wed, 11/09/2005 - 20:24

Forgive me if you have already covered this...

In classical physics we are given seven 'Fundamental Units'.

    Quantity

    Distance/Length
    Mass
    Time
    Electrical Charge
    Temperature
    Number
    Light Intensity

    Classical Unit

    meter (m)
    gram (g)
    second (s)
    coulomb (C)
    kelvin (K)
    mole (mol)
    condela (cd)

    Space/Time Unit
    meter (m)
    ?
    seconds (s)
    ?
    ?
    ?
    ?

Now, electrical charge, temperature and light intensity are all forms of energy, so are all three different units needed?

The mole is unneeded as a fundimental unit, due to the fact that it is only a number.

So, how do I fill in the unknown spaces in the chart.

Forums:

bperet's picture

bperet

Sat, 11/12/2005 - 09:37

Quantity

  • Distance/Length -- s
  • Mass -- t3/s3 (from E=mc2)
  • Time -- t
  • Electrical Charge -- s for quantity of charge, t/s for energy of charge (physics doesn't recognize the difference)
  • Temperature -- thermal=frequency (s/t or t/s depends on photon)
  • Number -- ONE (in natural units)
  • Light Intensity (condela) -- never heard of that one. Now is it derived?

BlueEagle wrote:
Now, electrical charge, temperature and light intensity are all forms of energy, so are all three different units needed?

No. Only space and time are needed. Energy is t/s.

But I should note that Larson discovered an error in legacy physics regarding electric charge, which sometimes appears as "s" (quantity), as in the area of a capacitor, and sometimes as "t/s", energy.

BlueEagle wrote:
The mole is unneeded as a fundimental unit, due to the fact that it is only a number.

You can calculate all these constants directly from natural units of space and time, based on what Larson outlined. But in the RS, they are reduced to their simplest terms, based on the speed of light, which is Unity -- 1 unit of space per 1 unit of time. All units can be expressed in terms of space and time.[/
BlueEagle's picture

BlueEagle

Thu, 11/17/2005 - 21:56

Quote:
Light Intensity (condela) -- never heard of that one. Now is it derived?

Not in legacy physics.

Sorry, I did spell it wrong though; "candela" which is the unit for "luminous intensity."

Quote:
Mass -- t3/s3 (from E=mc2)

E (energy) usually defined as Joules in legacy physics. Joules = (kg x m2)/s2 or (mass x distance2)/time2

How do you derive the unit for mass out of E=mc2?

Believing in Faith

bperet's picture

bperet

Tue, 11/22/2005 - 13:04

BlueEagle wrote:
Sorry, I did spell it wrong though; "candela" which is the unit for "luminous intensity."

We knew it as "candlepower" in my day.

www.electro-optical.com wrote:
The candela is the luminous intensity, in a given direction, of a source that emits monochromatic radiation of frequency 540 × 1012 hertz and that has a radiant intensity in that direction of 1/683 watt per steradian.

A "watt" is a measurement of power, in the RS having units of "1/s". It is derived from the equation: watts = voltage x current
1/s = t/s² x s/t, which is the product of force (voltage) and speed (current).

The "steradian" is just the fractional part of the surface of a sphere, which is there to adjust the focus of power along a beam (versus a radiant sphere), so being a percentage, has no units. So "candela" would be the same as "watts", 1/s.

BlueEagle wrote:
Quote:
Mass -- t3/s3 (from E=mc2)

E (energy) usually defined as Joules in legacy physics. Joules = (kg x m2)/s2 or (mass x distance2)/time2

How do you derive the unit for mass out of E=mc2?

Energy = t/s (inverse speed or work, time per unit distance).
"c" is the velocity of light, a speed, s/t.

E = m c2

t/s = m (s/t)2

m = (t/s) / (s/t)2

m = t3 / s3